42n^2=24n=0

Solution for 42n^2=24n=0 equation:

42n^2=24n=0

We move all terms to the left:

42n^2-(24n)=0

a = 42; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·42·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*42}=\frac{0}{84}
=0
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*42}=\frac{48}{84}
=4/7
$